Q...Q (2/5)
Anniversary 3 bln
f(x) = 13x + x! + x!!
f(5) = ??..
Nt : UwU![]()
Anniversary 3 bln
f(x) = 13x + x! + x!!
f(5) = ??..
Nt : UwU
°•°Jawaban°•°
f (x) = 13x + x! + x!!
f (5) = 13(5) + 5! + 5!!
f (5) = 65 + (5 x 4 x 3 x 2 x 1) + (5 x 3 x 1)
f (5) = 65 + (20 x 3 x 2 x 1) + (15 x 1)
f (5) = 65 + (60 x 2 x 1) + 15
f (5) = 65 + (120 x 1) + 15
f (5) = 65 + 120 + 15
f (5) = 185 + 15
f (5) = 200 √
[tex]\purple{\boxed{\boxed{\pink{»Answer by:シ⎝⎝PutririYandAni⎠⎠シ}}}}[/tex]
Penjelasan dengan langkah-langkah:
f(x) = 13x + x! + x!!
f(5) = 13(5) + 5! + 5!!
= ( 13 × 5 ) + ( 5 × 4 × 3 × 2 × 1 ) + ( 5 × 3 × 1 )
= 65 + ( 20 × 3 × 2 × 1 ) + ( 15 × 1 )
= 65 + ( 60 × 2 × 1 ) + 15
= 65 + 120 + 15
= 185 + 15
= 200
#koreksi
[answer.2.content]
